Heroin at a glance
| Property | Value |
|---|
| Molar mass | 369.417 g/mol |
|---|
| Molecular weight | 369.417 u |
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| Chemical formula | C21H23NO5 |
|---|
| Monoisotopic mass | 369.157623 u |
|---|
| CAS number | 561-27-3 |
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| PubChem CID | 5462328 |
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How to calculate the molar mass of heroin
21 × 12.011 + 23 × 1.008 + 1 × 14.007 + 5 × 15.999 = 369.417 g/mol
- Count the atoms in C21H23NO5: C 21, H 23, N 1, O 5.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 369.417 g/mol.
Elemental composition of heroin
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 21 | 12.011 | 252.231 | 68.278% |
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| H Hydrogen | 23 | 1.008 | 23.184 | 6.2758% |
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| N Nitrogen | 1 | 14.007 | 14.007 | 3.7917% |
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| O Oxygen | 5 | 15.999 | 79.995 | 21.654% |
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Grams and moles of heroin
| Amount | Equals |
|---|
| 1 g | 0.002707 mol |
|---|
| 10 g | 0.02707 mol |
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| 100 g | 0.2707 mol |
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| 0.1 mol | 36.942 g |
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| 1 mol | 369.42 g |
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| 1 g, in particles | 1.6302 × 10^21 |
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Calculate other compounds