Glucose Monohydrate at a glance
| Property | Value |
|---|
| Molar mass | 198.171 g/mol |
|---|
| Molecular weight | 198.171 u |
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| Chemical formula | C6H12O6·H2O |
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| Monoisotopic mass | 198.073953 u |
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| CAS number | 77938-63-7 |
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| PubChem CID | 22814120 |
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How to calculate the molar mass of glucose monohydrate
6 × 12.011 + 14 × 1.008 + 7 × 15.999 = 198.171 g/mol
- Count the atoms in C6H12O6·H2O: C 6, H 14, O 7.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 198.171 g/mol.
Elemental composition of glucose monohydrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 6 | 12.011 | 72.066 | 36.366% |
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| H Hydrogen | 14 | 1.008 | 14.112 | 7.1211% |
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| O Oxygen | 7 | 15.999 | 111.993 | 56.513% |
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Grams and moles of glucose monohydrate
| Amount | Equals |
|---|
| 1 g | 0.0050461 mol |
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| 10 g | 0.050461 mol |
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| 100 g | 0.50461 mol |
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| 0.1 mol | 19.817 g |
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| 1 mol | 198.17 g |
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| 1 g, in particles | 3.0389 × 10^21 |
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Calculate other compounds