Ferrous Fumarate at a glance
| Property | Value |
|---|
| Molar mass | 169.901 g/mol |
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| Molecular weight | 169.901 u |
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| Chemical formula | C4H2FeO4 |
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| Monoisotopic mass | 169.930245 u |
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| CAS number | 141-01-5 |
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| PubChem CID | 6433164 |
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How to calculate the molar mass of ferrous fumarate
4 × 12.011 + 2 × 1.008 + 1 × 55.845 + 4 × 15.999 = 169.901 g/mol
- Count the atoms in C4H2FeO4: C 4, H 2, Fe 1, O 4.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 169.901 g/mol.
Elemental composition of ferrous fumarate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 4 | 12.011 | 48.044 | 28.278% |
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| H Hydrogen | 2 | 1.008 | 2.016 | 1.1866% |
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| Fe Iron | 1 | 55.845 | 55.845 | 32.869% |
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| O Oxygen | 4 | 15.999 | 63.996 | 37.667% |
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Grams and moles of ferrous fumarate
| Amount | Equals |
|---|
| 1 g | 0.0058858 mol |
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| 10 g | 0.058858 mol |
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| 100 g | 0.58858 mol |
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| 0.1 mol | 16.99 g |
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| 1 mol | 169.9 g |
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| 1 g, in particles | 3.5445 × 10^21 |
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Calculate other compounds