Ethidium Bromide at a glance
| Property | Value |
|---|
| Molar mass | 394.316 g/mol |
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| Molecular weight | 394.316 u |
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| Chemical formula | C21H20BrN3 |
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| Monoisotopic mass | 393.08406 u |
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| CAS number | 1239-45-8 |
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| PubChem CID | 14710 |
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How to calculate the molar mass of ethidium bromide
21 × 12.011 + 20 × 1.008 + 1 × 79.904 + 3 × 14.007 = 394.316 g/mol
- Count the atoms in C21H20BrN3: C 21, H 20, Br 1, N 3.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 394.316 g/mol.
Elemental composition of ethidium bromide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 21 | 12.011 | 252.231 | 63.967% |
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| H Hydrogen | 20 | 1.008 | 20.16 | 5.1127% |
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| Br Bromine | 1 | 79.904 | 79.904 | 20.264% |
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| N Nitrogen | 3 | 14.007 | 42.021 | 10.657% |
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Grams and moles of ethidium bromide
| Amount | Equals |
|---|
| 1 g | 0.002536 mol |
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| 10 g | 0.02536 mol |
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| 100 g | 0.2536 mol |
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| 0.1 mol | 39.432 g |
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| 1 mol | 394.32 g |
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| 1 g, in particles | 1.5272 × 10^21 |
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