Dithiothreitol at a glance
| Property | Value |
|---|
| Molar mass | 154.242 g/mol |
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| Molecular weight | 154.242 u |
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| Chemical formula | C4H10O2S2 |
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| Monoisotopic mass | 154.012222 u |
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| CAS number | 3483-12-3 |
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| PubChem CID | 439196 |
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How to calculate the molar mass of dithiothreitol
4 × 12.011 + 10 × 1.008 + 2 × 15.999 + 2 × 32.06 = 154.242 g/mol
- Count the atoms in C4H10O2S2: C 4, H 10, O 2, S 2.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 154.242 g/mol.
Elemental composition of dithiothreitol
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 4 | 12.011 | 48.044 | 31.148% |
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| H Hydrogen | 10 | 1.008 | 10.08 | 6.5352% |
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| O Oxygen | 2 | 15.999 | 31.998 | 20.745% |
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| S Sulfur | 2 | 32.06 | 64.12 | 41.571% |
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Grams and moles of dithiothreitol
| Amount | Equals |
|---|
| 1 g | 0.0064833 mol |
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| 10 g | 0.064833 mol |
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| 100 g | 0.64833 mol |
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| 0.1 mol | 15.424 g |
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| 1 mol | 154.24 g |
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| 1 g, in particles | 3.9043 × 10^21 |
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Calculate other compounds