Camphor at a glance
| Property | Value |
|---|
| Molar mass | 152.237 g/mol |
|---|
| Molecular weight | 152.237 u |
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| Chemical formula | C10H16O |
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| Monoisotopic mass | 152.120115 u |
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| CAS number | 76-22-2 |
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| PubChem CID | 2537 |
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How to calculate the molar mass of camphor
10 × 12.011 + 16 × 1.008 + 1 × 15.999 = 152.237 g/mol
- Count the atoms in C10H16O: C 10, H 16, O 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 152.237 g/mol.
Elemental composition of camphor
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 10 | 12.011 | 120.11 | 78.897% |
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| H Hydrogen | 16 | 1.008 | 16.128 | 10.594% |
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| O Oxygen | 1 | 15.999 | 15.999 | 10.509% |
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Grams and moles of camphor
| Amount | Equals |
|---|
| 1 g | 0.0065687 mol |
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| 10 g | 0.065687 mol |
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| 100 g | 0.65687 mol |
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| 0.1 mol | 15.224 g |
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| 1 mol | 152.24 g |
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| 1 g, in particles | 3.9558 × 10^21 |
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Calculate other compounds