Calcium Nitrate Tetrahydrate at a glance
| Property | Value |
|---|
| Molar mass | 236.146 g/mol |
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| Molecular weight | 236.146 u |
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| Chemical formula | Ca(NO3)2·4H2O |
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| Monoisotopic mass | 235.980485 u |
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| CAS number | 13477-34-4 |
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| PubChem CID | 16211656 |
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How to calculate the molar mass of calcium nitrate tetrahydrate
1 × 40.078 + 2 × 14.007 + 10 × 15.999 + 8 × 1.008 = 236.146 g/mol
- Count the atoms in Ca(NO3)2·4H2O: Ca 1, N 2, O 10, H 8.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 236.146 g/mol.
Elemental composition of calcium nitrate tetrahydrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Ca Calcium | 1 | 40.078 | 40.078 | 16.972% |
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| N Nitrogen | 2 | 14.007 | 28.014 | 11.863% |
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| O Oxygen | 10 | 15.999 | 159.99 | 67.75% |
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| H Hydrogen | 8 | 1.008 | 8.064 | 3.4148% |
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Grams and moles of calcium nitrate tetrahydrate
| Amount | Equals |
|---|
| 1 g | 0.0042347 mol |
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| 10 g | 0.042347 mol |
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| 100 g | 0.42347 mol |
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| 0.1 mol | 23.615 g |
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| 1 mol | 236.15 g |
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| 1 g, in particles | 2.5502 × 10^21 |
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