Calcium Citrate at a glance
| Property | Value |
|---|
| Molar mass | 498.432 g/mol |
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| Molecular weight | 498.432 u |
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| Chemical formula | Ca3(C6H5O7)2 |
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| Monoisotopic mass | 497.894828 u |
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| CAS number | 813-94-5 |
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| PubChem CID | 13136 |
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How to calculate the molar mass of calcium citrate
3 × 40.078 + 12 × 12.011 + 10 × 1.008 + 14 × 15.999 = 498.432 g/mol
- Count the atoms in Ca3(C6H5O7)2: Ca 3, C 12, H 10, O 14.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 498.432 g/mol.
Elemental composition of calcium citrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Ca Calcium | 3 | 40.078 | 120.234 | 24.122% |
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| C Carbon | 12 | 12.011 | 144.132 | 28.917% |
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| H Hydrogen | 10 | 1.008 | 10.08 | 2.0223% |
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| O Oxygen | 14 | 15.999 | 223.986 | 44.938% |
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Grams and moles of calcium citrate
| Amount | Equals |
|---|
| 1 g | 0.0020063 mol |
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| 10 g | 0.020063 mol |
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| 100 g | 0.20063 mol |
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| 0.1 mol | 49.843 g |
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| 1 mol | 498.43 g |
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| 1 g, in particles | 1.2082 × 10^21 |
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