Boric Acid at a glance
| Property | Value |
|---|
| Molar mass | 61.831 g/mol |
|---|
| Molecular weight | 61.831 u |
|---|
| Chemical formula | H3BO3 |
|---|
| Monoisotopic mass | 62.0175243 u |
|---|
| CAS number | 10043-35-3 |
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| PubChem CID | 7628 |
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How to calculate the molar mass of boric acid
3 × 1.008 + 1 × 10.81 + 3 × 15.999 = 61.831 g/mol
- Count the atoms in H3BO3: H 3, B 1, O 3.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 61.831 g/mol.
Elemental composition of boric acid
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| H Hydrogen | 3 | 1.008 | 3.024 | 4.8908% |
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| B Boron | 1 | 10.81 | 10.81 | 17.483% |
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| O Oxygen | 3 | 15.999 | 47.997 | 77.626% |
|---|
Grams and moles of boric acid
| Amount | Equals |
|---|
| 1 g | 0.016173 mol |
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| 10 g | 0.16173 mol |
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| 100 g | 1.6173 mol |
|---|
| 0.1 mol | 6.1831 g |
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| 1 mol | 61.831 g |
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| 1 g, in particles | 9.7397 × 10^21 |
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Calculate other compounds