Ammonium Acetate at a glance
| Property | Value |
|---|
| Molar mass | 77.083 g/mol |
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| Molecular weight | 77.083 u |
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| Chemical formula | CH3COONH4 |
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| Monoisotopic mass | 77.0476785 u |
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| CAS number | 631-61-8 |
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| PubChem CID | 517165 |
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How to calculate the molar mass of ammonium acetate
2 × 12.011 + 7 × 1.008 + 2 × 15.999 + 1 × 14.007 = 77.083 g/mol
- Count the atoms in CH3COONH4: C 2, H 7, O 2, N 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 77.083 g/mol.
Elemental composition of ammonium acetate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 2 | 12.011 | 24.022 | 31.164% |
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| H Hydrogen | 7 | 1.008 | 7.056 | 9.1538% |
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| O Oxygen | 2 | 15.999 | 31.998 | 41.511% |
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| N Nitrogen | 1 | 14.007 | 14.007 | 18.171% |
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Grams and moles of ammonium acetate
| Amount | Equals |
|---|
| 1 g | 0.012973 mol |
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| 10 g | 0.12973 mol |
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| 100 g | 1.2973 mol |
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| 0.1 mol | 7.7083 g |
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| 1 mol | 77.083 g |
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| 1 g, in particles | 7.8125 × 10^21 |
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Calculate other compounds