Aluminum Hydroxide at a glance
| Property | Value |
|---|
| Molar mass | 78.003 g/mol |
|---|
| Molecular weight | 78.003 u |
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| Chemical formula | Al(OH)3 |
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| Monoisotopic mass | 77.9897575 u |
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| CAS number | 21645-51-2 |
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| PubChem CID | 10176082 |
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How to calculate the molar mass of aluminum hydroxide
1 × 26.982 + 3 × 15.999 + 3 × 1.008 = 78.003 g/mol
- Count the atoms in Al(OH)3: Al 1, O 3, H 3.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 78.003 g/mol.
Elemental composition of aluminum hydroxide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Al Aluminum | 1 | 26.982 | 26.982 | 34.591% |
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| O Oxygen | 3 | 15.999 | 47.997 | 61.532% |
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| H Hydrogen | 3 | 1.008 | 3.024 | 3.8768% |
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Grams and moles of aluminum hydroxide
| Amount | Equals |
|---|
| 1 g | 0.01282 mol |
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| 10 g | 0.1282 mol |
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| 100 g | 1.282 mol |
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| 0.1 mol | 7.8003 g |
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| 1 mol | 78.003 g |
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| 1 g, in particles | 7.7204 × 10^21 |
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Calculate other compounds